4b^2+52b+48=0

Solution for 4b^2+52b+48=0 equation:

Simplifying
4b2 + 52b + 48 = 0

Reorder the terms:
48 + 52b + 4b2 = 0

Solving
48 + 52b + 4b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '4'.
4(12 + 13b + b2) = 0

Factor a trinomial.
4((12 + b)(1 + b)) = 0

Ignore the factor 4.
Subproblem 1
Set the factor '(12 + b)' equal to zero and attempt to solve:

Simplifying
12 + b = 0

Solving
12 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + b = 0 + -12

Combine like terms: 12 + -12 = 0
0 + b = 0 + -12
b = 0 + -12

Combine like terms: 0 + -12 = -12
b = -12

Simplifying
b = -12
Subproblem 2
Set the factor '(1 + b)' equal to zero and attempt to solve:

Simplifying
1 + b = 0

Solving
1 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + b = 0 + -1
b = 0 + -1

Combine like terms: 0 + -1 = -1
b = -1

Simplifying
b = -1
Solution
b = {-12, -1}